Noetherian rings have the Orzech property #
Main results #
IsNoetherian.injective_of_surjective_of_injective: ifMandNareR-modules for a ringR(not necessarily commutative),Mis Noetherian,i : N →ₗ[R] Mis injective,f : N →ₗ[R] Mis surjective, thenfis also injective.IsNoetherianRing.orzechProperty: Any Noetherian ring satisfies the Orzech property.
Orzech's theorem for Noetherian modules: if R is a ring (not necessarily commutative),
M and N are R-modules, M is Noetherian, i : N →ₗ[R] M is injective,
f : N →ₗ[R] M is surjective, then f is also injective. The proof here is adapted from
Djoković's paper Epimorphisms of modules which must be isomorphisms [djokovic1973],
utilizing LinearMap.iterateMapComap.
See also Orzech's original paper: Onto endomorphisms are isomorphisms [orzech1971].
Orzech's theorem for Noetherian modules: if R is a ring (not necessarily commutative),
M is a Noetherian R-module, N is a submodule, f : N →ₗ[R] M is surjective, then f is also
injective.
Any surjective endomorphism of a Noetherian module is injective.
Any surjective endomorphism of a Noetherian module is bijective.
If M ⊕ N embeds into M, for M Noetherian over R, then N is trivial.
If M ⊕ N embeds into M, for M Noetherian over R, then N is trivial.
Equations
Instances For
Any Noetherian ring satisfies Orzech property.
See also IsNoetherian.injective_of_surjective_of_submodule and
IsNoetherian.injective_of_surjective_of_injective.